1 min readApr 19, 2020
LeetCode Java Solutions
124. Binary Tree Maximum Path Sum
Hard
Given a non-empty binary tree, find the maximum path sum.
For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must contain at least one node and does not need to go through the root.
Example 1:
Input: [1,2,3] 1
/ \
2 3Output: 6
Example 2:
Input: [-10,9,20,null,null,15,7] -10
/ \
9 20
/ \
15 7Output: 42
Solution
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
int maxPathSum = Integer.MIN_VALUE;
public int maxPathSum(TreeNode root) {
pathSum(root);
return maxPathSum;
}
private int pathSum(TreeNode node){
if(node == null){
return 0;
}
int left = Math.max(0, pathSum(node.left));
int right = Math.max(0, pathSum(node.right));
maxPathSum = Math.max(maxPathSum, left+right+node.val);
return Math.max(left,right)+node.val;
}
}